If $\Gamma$ does not contain four collinear points, then $S/I_{\Gamma}$ has regularity $2$. The following computation shows that a random element of $Hom(\omega(-4),R/I_{\Gamma})$ is injective. Therefore Corollary 2.15 gives the corresponding doublings.
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Next, suppose $\Gamma$ is the set of six points span $\mathbb{P}^{3}$ and four are collinear. We first check that a random element of $Hom(\omega(-\gamma), R/I_{\Gamma})$ is not injective for $\gamma = 2$. When $\gamma\geq 3$, a general element is injective and we compute the Betti table of doubling of $I_{\Gamma}$ with a general element for $\gamma=3,4,5,6$.
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